Question

1.) 3 mol gas CH4 (STP) = .............................................................Liter
2.) 0,5 mol gas H2 (0 derajat C, 1 atm) = .........................................Liter
3.) 5,6 Liter gas NH3 (STP) =...........................................................mol
4.) 33,6 Liter gas CO2 (0 derajat C, 76 cmHG) =................................mol

Answer 1

1) V=mol x 22.4 (karena STP)
=3 x 22,4= 67,2 L
2) V=nRT/P
=0,5x0,082x273/1=11,19 L
3)V=mol/22,4 (karena STP)
V=5,6/22,4=0.25mol
4)n=RT/PV
=0,082x273/76x33,6=8,766x10^-3

Answer 2

1. V = mol x 22,4 = 3 x 22,4 = 67,2 Liter

2. (0°C, 1 atm = STP) ⇒ V = mol x 22,4 = 0,5 x 22,4 = 11,2 Liter

3.  mol = V/22,4 = 5,6/22,4 = 0,25 mol

4. (0°C, 76 cmHg=1atm ≡ STP) ⇒ mol = V/22,4 = 33,6/22,4 = 1,5 mol