Question

(0,2x - 3)²- 3 (0,3x+4)² +4(x-1,2)(x+1,2)
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Answer 1

(0,2x - 3)²- 3 (0,3x+4)² +4(x-1,2)(x+1,2)

(x-y)²=x²-2xy+y²
(x+y)²=x²+2xy+y²
(x-y)(x+y)=x²-y²

(0,2x)²-2*0,2x*3+3²-3((0,3x)²+2*0,3x*4+4²)+4(x²-(1,2)²)=
=0,04x²-1,2x+9-3(0,09x²+2,4x+16)+4x²-4*1,44=
=0,04x²-1,2x+9-0,27x²-7,2x-48+4x²-5,76=
=3,77x²-8,4x-44,76