Mógłby mi ktoś pomóc w takim równaniu: 21=(½x)/(0,2-x)²
D:R\{0,2}
21*(0,2-x)^2=1/2x
21*(0,04-0,4x+x^2)=1/2x
0,84-8,4x+21x^2=0,5x
21x^2-8,9x+0,84=0
Δ=79,21-4*21*0,84
Δ=8,65
x1=(8,9-√8,65)/42
x2=(8,9+√8,65)/42
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D:R\{0,2}
21*(0,2-x)^2=1/2x
21*(0,04-0,4x+x^2)=1/2x
0,84-8,4x+21x^2=0,5x
21x^2-8,9x+0,84=0
Δ=79,21-4*21*0,84
Δ=8,65
x1=(8,9-√8,65)/42
x2=(8,9+√8,65)/42