znajdz 4 najmniejsze kolejne liczby naturalne nieparzyste, ktorych suma jest podzielna przez 15
27, 29, 31, 33
(2n + 1) + (2n + 3) + (2n + 5) + (2n + 7 ) = 8n + 16 = 8*(n + 2)
zatem
8*( n + 2) = 15 *k
Niech k = 8
wtedy n + 2 = 15
n = 13
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Mamy
2*13 + 1 = 27
2*13 + 3 = 29
2*13 + 5 = 31
2*13 + 7 = 33
spr> 27 + 29 + 31 + 33 = 120 = 8*15
Odp. 27,29,31,33
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27, 29, 31, 33
(2n + 1) + (2n + 3) + (2n + 5) + (2n + 7 ) = 8n + 16 = 8*(n + 2)
zatem
8*( n + 2) = 15 *k
Niech k = 8
wtedy n + 2 = 15
n = 13
========
Mamy
2*13 + 1 = 27
2*13 + 3 = 29
2*13 + 5 = 31
2*13 + 7 = 33
spr> 27 + 29 + 31 + 33 = 120 = 8*15
Odp. 27,29,31,33
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