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(x+1)²=2(x+4)
x²+2x+1-2x-8=0
x²-7=0
(x+√7)(x-√7)=0
x∈{-√7, √7}
b)
(2x+1)(8x-1)=3²
16x²-2x+8x-1-9=0
16x²+6x-10=0 /:2
8x²+3x-5=0
Δ=9+4*8*5=9+160=169
x=1/16*(-3-13)=-1 v x=1/16*(-3+13)=10/16=5/8