Zmieszano dwa roztwory kwasu octowego (octu) 125 g dziesięcio-procentowego i 175 g pięcio-procentowego. Oblicz stężenie procentowe otrzymanego roztworu.
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mr₁=125g
Cp₁=10%
mr₂=175g
Cp₂=5%
Cp=ms/mr * 100%
Cp/100% * mr = ms
Cp₁/100% * mr₁=ms₁
ms₁=10%/100% * 125g = 12,5g
Cp₂/100% * mr₂ = 5%/100% * 175g = 8,75g
ms = ms₁+ms₂=12,5g + 8,75g = 21,25g
mr=mr₁+mr₂=125g + 175g = 300g
Cp=ms/mr*100%
Cp = 21,25g / 300g *100%
Cp≈7%
Cp=ms/mr • 100%
mr=125g+175g=300g
ms=?
ms I
125g-100%
x (g)-10%
x=125•10/100=12.5g
ms II
175g-100%
x (g)-5%
x=175•5/100=8.75g
ms=12.5g+8.75g=21.25g
Cp=21.25g/300g • 100%=7.08