Zmieszano 40g 20% roztworu chlorku potasu i 20g 8% roztworu chlorku potasu, a nastepnie z otrzymanego roztworu odparowano 10g wody. Oblicz stezenie proentowe otrzymanego roztworu.
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mr₁=40g
cp₁=20%
mr₂=20g
cp₂=8%
ms₁=20%·40g/100%=8g
ms₂=8%·20g/100%=1,6g
mr₂=40g+20g=60g
mr₃=60g-10g=50g
ms₃=8g+1,6g=9,6g
cp₃=ms₃/mr₃·100%=9,6g/50g·100%=19,2g
mr1=40g
Cp1=20%
ms1=Cp1*mr1/100%
ms1=20*40/100
ms1=8g
mr2=20g
Cp2=8%
ms2=Cp2*mr2/100%
ms2=8*20/100
ms2=1,6g
Po zmieszaniu i odparowaniu wody
ms=9,6g
mr=40+20-10=50g
Cp=ms*100%/mr
Cp = 9,6*100/50
Cp = 19,2%