Question

Zapisz w postaci sumy algebraicznej :

( x + 2 ) ³

( x - 3 ) ³

( 2x+1)³

(x - w pierwiastku 2 ) ³

Prosze o Rozwiazanie :)

Answer 1

( x + 2 )³=(x+2)(x+2)(x+2)=(x²+2x+2x+4)(x+2)=(x²+4x+4)(x+2)=x³+2x²+4x²+8x+4x+8=x³+6x²+12x+8

 

( x - 3 )³=(x-3)(x-3)(x-3)=(x²-6x+9)(x-3)=x³-3x²-6x²+18x+9x-27=x³-9x²+27x-27

 

( 2x+1)³=(2x+1)(2x+1)(2x+1)=(4x²+4x+1)(2x+1)=8x³+4x²+8x²+4x+2x+1=8x³+12x²+6x+1

 

(x - √2 )³=(x-√2)(x-√2)(x-√2)=(x²-2√2x+2)(x-√2)=x³-√2x²-2√2x²+4x+2x-2√2=x³-3√2x²+6x-2√2