Question

Zapisz podany iloczyn w postaci poteńki matematyka 2001

a)o,5 poteńga11*8poteńgi11

b)o,4poteńgi10*(-2,5)10

21do poteńgi 33* jedan sudma do poteńgi33

prosze szybko o ozwionzanie pilis

Answer 1

a)0,5¹¹*8¹¹= (0,5*8)¹¹=4¹¹

 

b)0,4¹⁰*(-2,5)¹⁰= [0,4*(-2,5)]¹⁰= (-1)¹⁰=1

 

21³³*(1/7)³³=(21*1/7)³³=3³³

Answer 2

a)

0,5^11 x 8^11 = (0,5 x 8)^11 = 4^11

b)

0,4^10 x (-2,5)^10 = (4/10)^10 x (-25/10)^10 = (2/5)^10 x (-5/2)^10 = 

= [2/5 x(-5/2)]^10 = (-1)^10 = 1

c)

21^33 x (1/7)^33 = (21 x 1/7)^33 = 3^33