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0,3n=m
podstawiamy drugi wzór pod pierwszy,czyli za m podstawiamy 0,3n
0,3n+n=65
1,3n=65
n=50
m=65-50=15
m + n = 65
n=65-,
m=0,3(65-m)
m=19,5-0,3n
1,3m=19,5 /:1,3
m=15
m+n=65
15+n=65
n=65-15
n=50
m=15
n=50