Zamień sumy na iloczyny:
5a+4b=
7-7a=
a(2-x)+b(2-x)=
2a(3x-2y)-2b(3x+2y)=
6x^2(a+b)+a+b=
(2x+3)^2+3x(2x+3)=
a(x-2y)-3b(x-2y)+2c(x-2y)=
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1*(5a+4b)
7(1-a)
(2-x)(a+b)
2[a(3x-2y)-b(3x+2y)]
(a+b)(6x^2+1)
(2x+3)(2x+3+3x)=(2x+3)(5x+3)
(x-2y)(a-3b+2c)
1*(5a+4b)
7(1-a)
(2-x)(a+b)
2[a(3x-2y)-b(3x+2y)]
(a+b)(6x^2+1)
(2x+3)(2x+3+3x)=(2x+3)(5x+3)
(x-2y)(a-3b+2c)