Zamień logarytm na logarytm o podstawie 3.
a) log₉ 2 =
b) log⅓ 5 =
wykorzystujemy wzór na zamianę podstawy logarytmu
a) log₉ 2 = (log₃2)/(log₃ 9)=(log₃2)/(log₃ 3²)= (log₃2)/2
log₃ 3²=2 ; log₃ 3⁻¹=-1
b) log⅓ 5 =(log₃5)/log₃(1/3)=(log₃5)/log₃(1/3)= (log₃5)/(log₃ 3⁻¹)= -log₃5
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wykorzystujemy wzór na zamianę podstawy logarytmu
a) log₉ 2 = (log₃2)/(log₃ 9)=(log₃2)/(log₃ 3²)= (log₃2)/2
log₃ 3²=2 ; log₃ 3⁻¹=-1
b) log⅓ 5 =(log₃5)/log₃(1/3)=(log₃5)/log₃(1/3)= (log₃5)/(log₃ 3⁻¹)= -log₃5