Zamień jednostki.
1. 795mΩ= ........hΩ
2. 0,78cβ=........ μβ
Możecie napisac jak do tego doszliscie?
795mΩ= 7950000hΩ
0,78cβ=7800μβ
1.
795 mΩ = 795* 10⁻³Ω = 0,795 Ω = 0,00795*10² Ω = 0,00795 hΩ
2.
0,78 cβ = 0,78*10⁻²β = 0,0078 β = 7800*10⁻⁶ β = 7800 μβ
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795mΩ= 7950000hΩ
0,78cβ=7800μβ
1.
795 mΩ = 795* 10⁻³Ω = 0,795 Ω = 0,00795*10² Ω = 0,00795 hΩ
2.
0,78 cβ = 0,78*10⁻²β = 0,0078 β = 7800*10⁻⁶ β = 7800 μβ