September 2018 2 15 Report

Zadanie1.

Rozwiąż metodą przeciwnych współczynników. :

 a )\left \{ {{10(y+2)+3(x-5)=x-5} \atop {25(y+2)+3(x-5)=-10}} \right

b) \left \{ {{2(2x-y)+3(x+3y)=42} \atop {5(x+3y)-8(2x-y)=-32}} \right

c) \left \{ {{\frac{y}2 + \frac x 4 - \frac 1 5 (x+2)= 1,1 \atop {x-2y+4 = \frac x 2 + \frac 3 4 ( y- 0 ,5)}} \right

Z góry dziękuje za pomoc. ; **


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