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a)to (4x²-12x+8-6+15x-9x²)(4x+5)=(-5x²+3x+2)(4x+5)=-20x³-25x²+12x²+15x+8x+10=-20x³-13x²+23x+10
b)to (2x+3)(5x²+10x-15+12-8x-4x²)=(2x+3)(x²+2x-3)=2x³+4x²-6x+3x²+6x-9=2x³-x²-9
c)to (4-3x)(-21+6x+9x²-10x²-10x+30)=(4x-3)(9-4x-x²)=36-16x-4x²-27x+12x²+3x³=3x³+8x²-11
d)to (-12x²-8x+10+15x²-5x-10)(x+3)=(3x²-13x)(x+3)=3x³+9x²-13x²-39x=3x³-4x²-39x=x(3x²-4x-39)
zad17
to (-4x²+40x+28+6x²-2x-9x+6)(2x-1)=(2x²+28x+34)(2x-1)=4x³-2x²+56x²-28x+68x-34=4x³+54x²+40x-34
zad18
to -4x²+10x-2-10+5x+5x²=x²+15x-12
podstawiamy za x 1
1²+15-12=1+15-12=16-12=4