Zadanie 11:
Oblicz sumę liczb:
a) 2√27, -3√48, -2√75, 2√108
Zadanie 12:
Oblicz iloczyn:
a) sumy 2√8 + 4√2 i liczby √2
2√27, -3√48, -2√75, 2√108 = 6√3 - 12√3 - 10√3 + 12√3 = -4√3
(2√8 + 4√2) * √2= (4√2+4√2) *√2 = 8√2 * √2 = 16
Pozdrawiam ;)
zad11oblicz sume liczb:
2√27+(-3√48)+(-2√75)+2√108=6√3+(-12√3)+(-10√3)+12√3=
6√3-12√3-10√3+12√3=-4√3
zad12 oblicz iloczyn:
(2√8+4√2)·√2=(4√2+4√2)·√2=8√2·√2=8·2=16
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2√27, -3√48, -2√75, 2√108 = 6√3 - 12√3 - 10√3 + 12√3 = -4√3
(2√8 + 4√2) * √2= (4√2+4√2) *√2 = 8√2 * √2 = 16
Pozdrawiam ;)
zad11oblicz sume liczb:
2√27+(-3√48)+(-2√75)+2√108=6√3+(-12√3)+(-10√3)+12√3=
6√3-12√3-10√3+12√3=-4√3
zad12 oblicz iloczyn:
(2√8+4√2)·√2=(4√2+4√2)·√2=8√2·√2=8·2=16