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d)
x+20kg - całkowita masa
30% * x + 0% *20 = 20%(x+20)
0,3*x = 0,2(x+20)
0,3x = 0,2x + 4
0,3x-0,2x = 4
0,1x = 4
x = 40
(x+20kg) = 40 + 20 = 60kg
odp: Całkowita masa syropu wynosi 60 kg.
Zad.11
a)
30 kg - solanka 2%;
(30 - x) kg - solanki 3%
2% × 30 = 3% × (30 - x)
2 × 30 / 100 = 3 × (30 - x) / 100
2× 30 = 3 × (30 - x)
60 = 90 - 3x
3 x = 90 - 60
3x=30 /:3
x = 10kg
Odp: Odparowano 10 kg wody .