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1346 + 1348 + 1350
zad 2
ma 17 pięciozłotówek i 119 dwuzłotówek bo
17 * 5 = 85
85 * 7 = 119
119 * 2 = 238
85 + 238 = 323
kolejne liczby parzyste:
2x
2x+2
2x+4
2x + 2x + 2 + 2x + 4 = 4044
6x + 6 = 4044
6x = 4038
x = 673
2x = 2×673 = 1346
2x + 2 = 2×673 + 2 = 1348
2x + 4 = 2×673 + 4 = 1350
odp: te liczby to: 1346, 1348, 1350
ZAD. 2.
x -złotówka
5x -pięciozłotówka
2x × 7 -dwuzłotówki
5x + 2x × 7 = 323
5x + 14x = 323
19x = 323
x = 17
7x = 7 × 17 = 119
odp: pięciozłotówek ma 17 sztuk, a dwuzłotówek 119