zadanie 1 oblicz
√ =13
∛ =-5
zadanie 2 oblicz
3√5²+ 2√5- 2∛(-5)³=
zadanie 3usuń niewymiernosci z mianownika
15√3
√5
to jest ułamek
zadanie 4 oblicz
√36+8²=
teraz znow bedzie ułamek
√36+√2
√2
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zad.2
odp;50
√169 = 13
∛-125 = -5
3√5²+2√5-2∛(-5)³ = 3·5 + 2√5 - 2·(-5)= 15+10+ 2√5 = 25+ 2√5
15 · √3÷√5 = 15 · 3 ÷ 5
√36 +8² = √36 + 64 = √100 = 10
√36+√2
√2 = 7