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stozek\ II: \\promien:\ \ r=9\ cm\\wysokosc:\ \ h=12 \ cm\\\\ V_{2}=\frac{1}{3}\pi r^2 h =\frac{1}{3}\ \pi*9^2*12=\frac{1}{3}\ \pi*81*4= 27*4\pi=108 \ \pi\ cm^3\\\\\\\frac{V_{2}}{V_{1}}=\frac{108\pi}{12\ \pi}=9\\\\odp.\ \ B. \ \ 9\ razy