Zadania w załączniku.
1,2,3,5.
1. B,D
2. B,D,E
3.
Dane:
ms (masa chlorowodoru) = 20g
mw (masa wody)= 180g
mr (masa roztworu)= ms + mw = 20g + 180g = 200g
C% = ?
* Obliczam stężenie procentowe (C%):C% = ms * 100% : mr = 20g * 100% : 200g = 20%
5.
mr = 0,5kg = 500g
C% = 38%
ms = ?
mw = ?
* Obliczam masę chlorowodoru (ms) zawartą w tym roztworze:
C% = ms * 100% : mr /*mr
C% * mr = ms * 100% /:100%
ms = C% * mr : 100% = 38* * 500g : 100% = 190g chlorowodoru
* Obliczam masę wody (mw) :
mr = ms + mw
mw = mr - ms = 500g - 190g = 310g wody
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1. B,D
2. B,D,E
3.
Dane:
ms (masa chlorowodoru) = 20g
mw (masa wody)= 180g
mr (masa roztworu)= ms + mw = 20g + 180g = 200g
C% = ?
* Obliczam stężenie procentowe (C%):
C% = ms * 100% : mr = 20g * 100% : 200g = 20%
5.
Dane:
mr = 0,5kg = 500g
C% = 38%
ms = ?
mw = ?
* Obliczam masę chlorowodoru (ms) zawartą w tym roztworze:
C% = ms * 100% : mr /*mr
C% * mr = ms * 100% /:100%
ms = C% * mr : 100% = 38* * 500g : 100% = 190g chlorowodoru
* Obliczam masę wody (mw) :
mr = ms + mw
mw = mr - ms = 500g - 190g = 310g wody