zad.1ile etanolu otrzymamy z 4 ton glukozy?
mC6H12O6=180u
mC2H5OH=46u
C6H12O6 ---drozdże--> 2C2H5OH + 2CO2
180g glukozy ------- 2*46g etanolu
4 tony glukozy ------ x ton etanolu
x = 2,04 tony etanolu
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mC6H12O6=180u
mC2H5OH=46u
C6H12O6 ---drozdże--> 2C2H5OH + 2CO2
180g glukozy ------- 2*46g etanolu
4 tony glukozy ------ x ton etanolu
x = 2,04 tony etanolu