Zad1. Wykonaj działania
a) 4 (x + 3) =
b) 8 (y + 4) =
c)5 (-2a + b) =
d) -4 (5y -z) =
Zad2. Zamień iloczyn na sumę
a) 3 (x - 3)= b) 5 (y+z) =
c) 4 (3x - y) = d) 3 (4a - c) =
e) -2 (7 - 4n) =
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1. a) 4(x+3)= 4x + 12
b) 8(y+4)= 8y + 24
c) 5 (y+4)= 5y + 20
d) -4(5y-z)= -20y --4z
dalej nie rozumiem. :)
zad 1
a) 4x+12
b)8y+32
c)-10a+5b
d)-20y+4z
zad 2
a)-9+3x
b)5y+5z
c)-4y+12x
d)-3c+12a
e)-14+8n