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b)12x2 10x2 4x4
40=0.5*10q
q=8
bok rombu liczymy z tw.Pitagorasa a²+b²=c²
5²+4²=c²
25+16=c²
c=√41
Obw=4√41
b)obliczamy 4 bok z Pitagorasa 16+4=c²; c=√20=2√5
obw=10+4+12+2√5=26+2√5