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1/x + 1/y + 1/z = 1 / xyz
x* z + y * x+ y * z = 27
x + y + z = 9
yz + xz + xy = xyz
yz + xz + xy= 27
odejmuję równanie 3 od 2
x + y + z = 9
xyz - 27 = 0
x + y + z = 9
xyz = 27
27 = 3*3*3 i nie ma innej opcji
x=3
y=3
z=3