Question

Diberikan
(1 + ¹/x) = 10
(1 + ¹/y) = 25
(1 + ¹/z) = 40
dengan x,y,z ≠ 0
Tentukan nilai [xyz + 1/(xyz)].



@ Wello1
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Answer 1

Misal :
1/x = a
1/y = b
1/z = c

1 + 1/x = 10
1 + a = 10
a = 10 - 1 = 9
1/x = a
x = 1/a = 1/9

1 + 1/y = 25
1 + b = 25
b = 25 - 1 = 24
1/y = b
y = 1/b = 1/24

1 + 1/z = 40
1 + c = 40
c = 40 - 1 = 39
1/z = c
z = 1/c = 1/39

xyz + 1/(xyz)
= 1/9 × 1/24 × 1/39 + 1/(1/9 × 1/24 × 1/39)
= 1/8424 + 1/(1/8424)
= 1/8424 + 8424
= 8424 1/8424

maaf kalo salah
semoga membantu

Answer 2

1/x = 9 ; 1/y = 24 ; 1/z = 39

xyz = 1/8424

xyz + 1/xyz = 1/8424 + 8424
                   = 8424 + 1/8424
                   = ((8424)²+1)/8424
                   = (70.963.777)/8424