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x(x + 3) = 5x + 3
x² + 3x = 5x + 3
x² + 3x - 5x - 3 = 0
x² - 2x - 3 = 0 Factorizas trinomio de la forma x² + bx + c
(x - 3)(x + 1) = 0 Tiene 2 soluciones reales
x - 3 = 0
x = 3
o
x + 1 = 0
x = - 1
Comprobacion.
Para x = 3
x(x + 3) = 5x + 3
3(3+ 3) = 5 * 3 + 3
3 * 6 = 15 + 3
18 = 18
Para x = - 1
-1( - 1 + 3) = 5 * ( -1) + 3
- 1 (2) = - 5 + 3
- 2 = -2
Solucion.
(3 , - 1)