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∫ (1/x³+6/x⁷) dx
=( x⁻³+6x⁻⁷) dx
=( -1/2 x⁻²+ -x⁻⁶+C)
=(-1/2 x⁻² - 1/x⁶ + C)
Pilihan A.paling mendekati.
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