Question

Oblicz granice.
Limx->-4 x^3+3x^2-4x/x^2+7x+12

Answer 1

X³+3x²-4x=x(x²+3x-4)=x((x²-x)+(4x-4))=x(x(x-1)+4(x-1))=x(x-1)(x+4)
x²+7x+12=(x²+3x)+(4x+12)=x(x+3)+4(x+3)=(x+3)(x+4)
toz mamy
lim x→-4 x(x-1)(x+4)/(x+3)(x+4)=lim x→-4 x(x-1)/x+3=-4(-4-1)/-4+3=20/-1=-20
Odpowiedz -20