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P(2,3) => f(2)=3
3/2+a=3 / *2+a
3=6+3a
3a=-3
a=-1
a)
f(x)=-(x-2)²+3 - iloczynowa
f(x)=-(x²-4x+4)+3=-x²+4x²-4+3
f(x)=-x²+4x²-1 - ogólna
b) Δ=16-4(-1*(-1))=16-4=12
√Δ=√12=2√3
x₁=-4-2√3/-2=2+√3
x₂=-4+2√3/-2=2-√3