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F(x) = 1/x+2(f○g)(x) = 1/x^2+3
f(g(x)) = 1/x^2+3
1/g(x)+2 = 1/x^2+3
g(x) = x^2+3-2
g(x) = x^2+1
g(x-1) = (x-1)^2+1
g(x-1) = x^2-2x+1+1
g(x-1) = x^2-2x+2
Jadi g(x-1) = x^2 - 2x + 2