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Bab Program LinearMatematika SMA Kelas XI
x + 2y = 16
x + y = 12
---------------- -
y = 4
x + y = 12
x + 4 = 12
x = 12 - 4
x = 8
titik potongnya (8, 4)
x + y = 12 → (12, 0) dan 0,12)
x + 2y = 16 → (16, 0) dan (0, 8)
karena minimum, ambil titik yang tinggi yaitu (16, 0) dan (0,12)
nilia minimum =
f(x, y) = 3x + 5y
f(16, 0) = 3 . 16 + 5 . 0 = 48
f(0, 12) = 3 . 0 + 5 . 12 = 60
f(8, 4) = 3 . 8 + 5 . 4 = 44
jadi, nilai minimumnya adalah 44