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(x + 1)(2 - x) = 2(x + 1)
2x + 2 - x² - x = 2x + 2
- x² + x - 2x + 2 - 2 = 0
- x² - x = 0
-x(x - 1) = 0
- x = 0
x = 0
x - 1 = 0
x = 1
x = 0 lub x = 1
2-x = |·(x+1)
(2-x)(x+1)=2
2x+2-x²-x=2
-x²+x=0
-x(x+1)=0
-x=0 ∨ x+1=0
x=0 ∨ x=-1