Question

x³-x²-3x+6=0

x³+4x²-9x-36=0

x³-2x²-8x=0

x³+5x²+6x=0

Answer 1

x³-x²-3x+6=0

(x³-x²) + (-3x+6) =0

x²(x-1) -3(x-1) =0

(x²-3)(x-1) =0

x²-3=0 lub x-1 = 0

x=√3

x=-√3

x=1

 

x³+4x²-9x-36=0

(x³+4x²)+(-9x-36)=0

(x²-9)(x+4)=0

x=3

x=-3

x=-4

 

 

x³-2x²-8x=0

x(x²-2x-8)=0

Δ=36

√Δ=6

x1=-2

x2=4

Odp.

x=0

x=-2

x=4

 

 

 

x³+5x²+6x=0

x(x²+5x+6)=0

Δ=1

√Δ=1

x1= -3

x2=-2

 

Odp.

x=0

x=-3

x=-2