f(x) = x-2/√-x
D: -x > 0 => x < 0
x ∈ (-oo; 0)
f(x) = 0 <=> x - 2 = 0 => x = 2 ∉ D zatem nie ma miejsc zerowych
f(-9) = -9-2/√9 = -11/3
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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f(x) = x-2/√-x
D: -x > 0 => x < 0
x ∈ (-oo; 0)
f(x) = 0 <=> x - 2 = 0 => x = 2 ∉ D zatem nie ma miejsc zerowych
f(-9) = -9-2/√9 = -11/3
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)