y=ax+b
a=tgα, α - kat nachylenia prostej do osi OX
tg120⁰=tg(180⁰-60⁰)=-tg60⁰=-√3
b=3
Odp. f(x)=-√3x+3
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y=ax+b
a=tgα, α - kat nachylenia prostej do osi OX
tg120⁰=tg(180⁰-60⁰)=-tg60⁰=-√3
b=3
Odp. f(x)=-√3x+3