wyznacz wspolrzedne srodka okregu opisanego na trojkacie o wierzcholkach a(-2,0) b(6,0) c (4,6)
S(x;y) P(xa, ya)
ISPI=√(xa-x)²+(ya-y)²
(x+2)²+y²=(x-6)² +y²
x²+4x+4=x²-12x+36
16x=32
x=2
(2-4)²+(y-6)²=(2+2)²+y²
4+y²-12y+36=16+y²
-12y= -24
y= 2
S(2;2)
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S(x;y) P(xa, ya)
ISPI=√(xa-x)²+(ya-y)²
(x+2)²+y²=(x-6)² +y²
x²+4x+4=x²-12x+36
16x=32
x=2
(2-4)²+(y-6)²=(2+2)²+y²
4+y²-12y+36=16+y²
-12y= -24
y= 2
S(2;2)