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miejsca zerowe: x1=-5, x2=2
y=a(x+5)(x-2)
f(-3)=a*2*(-5)=10
-10a=10
a=-1
y=-(x+5)(x-2)
y=-x²-3x+10
b)
x1=1, x2=3
y=a(x-1)(x-3)
f(0)=-a*(-3)=-9
3a=-9
a=-3
y=-3(x-1)(x-3)
y=-3(x²-4x+3)=-3x²+12x-9