wyznacz pole trojkata rownobocznego majac 2 wierzcholki a=-3 ,1 .b -6, 4
|AB|²=(-6+3)²+(4-1)²=9+9=18
|AB|=√18=3√2
P=a²√3/4
P=18√3/4=4,5√3
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|AB|²=(-6+3)²+(4-1)²=9+9=18
|AB|=√18=3√2
P=a²√3/4
P=18√3/4=4,5√3