Wyznacz pierwiastki wielomianu :
b) Q(x)=x(x+2)(x+3)
d) Q(x)=-5x(x+2)(x+1)
b) x= -2 x= -3 x= 0
d) x =0 x= -2 x= -1
a)
Q(x) = x(x+2)(x+3)
x=0 lub x+2 = 0 lub x+3 = 0
x = -2 lub x = -3
b)
Q(x) = -5x(x+2)(x+1)
-5x = 0 lub x+2 = 0 lub x+1 = 0
x = 0 lub x = -2 lub x = -1
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b) x= -2 x= -3 x= 0
d) x =0 x= -2 x= -1
a)
Q(x) = x(x+2)(x+3)
x=0 lub x+2 = 0 lub x+3 = 0
x = -2 lub x = -3
b)
Q(x) = -5x(x+2)(x+1)
-5x = 0 lub x+2 = 0 lub x+1 = 0
x = 0 lub x = -2 lub x = -1