Question

Wyznacz pierwiastki wielomianu : b) Q(x)=x(x+2)(x+3) d) Q(x)=-5x(x+2)(x+1)

Answer 1

a)

Q(x) = x(x+2)(x+3)

Q(x) = 0

x(x+2)(x+3) = 0

x = 0

lub

x+2 = 0   => x = -2

lub

x+3 = 0   => x = -3

Odp. x = -3   v   x = -2   v   x = 0 

 

d)

Q(x) = -5x(x+2)(x+1)

Q(x) = 0

-5x(x+2)(x+1) = 0

-5x = 0    => x = 0

lub

x+2 = 0   => x = -2  

lub

x+1 = 0   => x = -1

Odp. x = -2   v   x = -1   v   x = 0