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Pp- pole podstawy
H - wys. ostrosłupa
Pp=a²
H=?
Z tw. Pitagorasa:
H²+(½a√2)=a²
H²+¼*2*a²=a²
H²=a²-½a²
H²=½a²
H=a√2/2
V=⅓*a²*a√2/2= ⅙a³√2
V=a³√2/6
/-kreska ułamkowa