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r1 = 1
h1 = 3
V1 = π1\2 * 3 = 1π * 3 = 3π
V1 = 3π
V2 = πr2\2 * h2
r2 = ?
r2 = 2 * r1
r2 = 2 * 1
r2 = 2
h2 = ?
h2 = h1 : 3
h2 = 3 : 3
h2 = 1
V2 = π2\2 * 1 = 4π * 1 = 4π
V2 = 4π
V2 : V1 = ?
4π : 3π = 4/3 = 1 1/3 (4pi : 3pi = 4/3 = 1 i 1/3)
Odp.: Objętość walca zwiększy się 1 1/3 - ?krotnie?.