Wyznacz miejsca zerowe funkcji f(x)=2x²-11x+9
Δ=121-4*2*9
Δ=121-72
Δ=49
√Δ=7
x1=(11-7)/4=1
x2=(11+7)/4=4,5
2x²-11x+9=0
Δ=b²-4ac
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Δ=121-4*2*9
Δ=121-72
Δ=49
√Δ=7
x1=(11-7)/4=1
x2=(11+7)/4=4,5
2x²-11x+9=0
Δ=b²-4ac
Δ=121-4*2*9
Δ=49
√Δ=7