Wyznacz liczbe x, wiedzac, ze log2(x -1) = -3.
zal: x-1>0
d: (1,∞)
i co dalej? tylko prosze o wytlumaczenia w miare dokladne
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x -1
+ 1 = x
+ 1 = x
x =
log2(x-1) = -3
2^-3 = x -1
x = 1 i 1/8