wyznacz liczbe wyrazow ciagu arytmetycznego majac dane Sn= 456 r= -12 an= 12
Sn=(a1+an)/2
456=(a1+12)/2
a1+12=912
a1=900
an=a1+(n-1)r
12=900+(n-1)*(-12)
-888=-12*(n-1)
74=n-1
n=75
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Sn=(a1+an)/2
456=(a1+12)/2
a1+12=912
a1=900
an=a1+(n-1)r
12=900+(n-1)*(-12)
-888=-12*(n-1)
74=n-1
n=75