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360g
C₆H₁₂O₆ --->2C₂H₅OH + 2CO₂
2 mole 2 mole
Oblizamy masę glukozy
MC₆H₁₂O₆ =6 * 12g + 12 * 1g + 6 * 16g = 72g + 12g + 96g = 180g/mol
układamy proporcje
180g C₆H₁₂O₆ ------------- 2mole C₂H₅OH
360g C₆H₁₂O₆ ----------- xmoli C₂H₅OH
x = 360g * 2mole / 180g
x = 4 mole C₂H₅OH
180g C₆H₁₂O₆ ------------- 2mole CO₂
360g C₆H₁₂O₆ ----------- xmoli CO₂
x = 360g * 2mole / 180g
x = 4 mole CO₂
x mol - 360g
x=2 mol
1mol 2mol 2mol
C₆H₁₂O₆--->2C₂H₅OH+2CO₂
2mol x x
1mol - 2mol
2mol - x
x=4 mol