Wykonaj działanie.
(2x²-3x)²+(x²+4x)²=
4x^4 - 12x^3 + 9x^2 + x^4 + 8x^3 +16x^2 =
5x^4 - 4x^3 + 25x^2 =
x^2(5x^2 - 4x + 25)
x^2 = 0
x = 0
Δ = 16 - 500
Δ < 0
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
4x^4 - 12x^3 + 9x^2 + x^4 + 8x^3 +16x^2 =
5x^4 - 4x^3 + 25x^2 =
x^2(5x^2 - 4x + 25)
x^2 = 0
x = 0
Δ = 16 - 500
Δ < 0