Wykaż,że różnica kwadratów dwóch kolejnych licz nieparzystych jest podzielna przez 8.
daje naj! :P
(2n+1)²-(2n+3)²=
4n²+4n+1-(4n²+12n+9)=
4n²+4n+1-4n²-12n-9=
-8n-8=-8(n+1)
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(2n+1)²-(2n+3)²=
4n²+4n+1-(4n²+12n+9)=
4n²+4n+1-4n²-12n-9=
-8n-8=-8(n+1)