wykaż, że:
log₄81+log₁₆81=log₂27
loga b=(logc b)/(logc a)
log₂81 log₂81
-------- + --------- = 1/2 log₂81 + 1/4 log₂81=3/4 log₂81 = log₂ (81^3/4)
log₂4 log₂16
log₂ (81^3/4)=log₂27
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loga b=(logc b)/(logc a)
log₄81+log₁₆81=log₂27
log₂81 log₂81
-------- + --------- = 1/2 log₂81 + 1/4 log₂81=3/4 log₂81 = log₂ (81^3/4)
log₂4 log₂16
log₂ (81^3/4)=log₂27